Trigonometry
posted by Taylor on .
How do you factor and simplify,
1sin^3x
and
sec^4x2sec^2xtan^2x+tan^4x

the first is the difference of two cubes:
(1a^3)=(1a)(1+a+a^2)
from...
a3 – b3 = (a – b)(a2 + ab + b2)
the second is very similar to
(a^22ab+b^2)..... 
I'm not positive, but the answer to 1sin^3 would be (1sinx)(1+sinx+sin^2x)