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July 30, 2014

July 30, 2014

Posted by **Taylor** on Sunday, January 3, 2010 at 2:31pm.

1-sin^3x

and

sec^4x-2sec^2xtan^2x+tan^4x

- Trigonometry -
**bobpursley**, Sunday, January 3, 2010 at 2:48pmthe first is the difference of two cubes:

(1-a^3)=(1-a)(1+a+a^2)

from...

a3 – b3 = (a – b)(a2 + ab + b2)

the second is very similar to

(a^2-2ab+b^2).....

- Trigonometry -
**Taylor**, Sunday, January 3, 2010 at 3:44pmI'm not positive, but the answer to 1-sin^3 would be (1-sinx)(1+sinx+sin^2x)

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