Friday

November 21, 2014

November 21, 2014

Posted by **Mary** on Sunday, January 3, 2010 at 1:57pm.

Solve over the complex numbers.

1/e + 1/(square root of e) - 6 = 0

- Algebra 2 -
**Reiny**, Sunday, January 3, 2010 at 2:16pmI would let √e = x , then

1/x^2 + 1/x - 6 = 0

multiply by x^2

1 + x - 6x^2 = 0

6x^2 - x - 1 = 0

(3x+1)(2x-1) = 0

x = -1/3 or x = 1/2

√e = -1/3 or √e = 1/2

e = 1/9 or e = 1/4

since we "squared" we have to verify all answers.

if e = 1/9

LS = 1/(1/9) + 1/√(1/9) - 6

= 9 + 3 - 6 = 6

RS = 0, so e = 1/9 does not work

if e = 1/4

LS = 4 + 2 - 6 = 0 = RS

so e = 1/4

BTW, most texts and authors would avoid using e as a variable, since e is generally accepted as the Euler constant

- Algebra 2 -
**Mary**, Sunday, January 3, 2010 at 2:45pmThank you so much! I've been stuck on this problem for over 2 hours

**Answer this Question**

**Related Questions**

Algebra - 1)Find the exact solutions to 3x^2=5x-1 using the quadratic formula. ...

algebra - 1.)correct 2.)wrong---> the first term is wrong 4(3a^2)^2 = 36a^4 3...

Complex numbers - quadratic formula - Let a and b be real numbers. The complex ...

Algebra - Use the quadratic formula to solve the equation. Give exact answers: ...

algebra - What would be the discriminant for this equation: x^2-2x+12=0 How many...

algebra - 1)Write the expression 9n^6+7n^3-6 in quadratic form,if possible A.9(n...

Math PLEASE HELP ASAP - -PLEASE INCLUDE SOLUTIONS AND EXPLAIN HOW YOU DID IT ...

algebra - 1)Find the exact solutions to 3x^2=5x-1 using the quadratic formula. ...

algebra - Help Fast PLEASE!! check for corrections on my problems 1.Rewrte the ...

Math - i^6 = (i^2)^3 = (-1)^3 = -1 The square, not the square root of -1 is 1...