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November 28, 2014

November 28, 2014

Posted by **Kimba** on Sunday, January 3, 2010 at 12:37am.

x=?

- Algebra -
**drwls**, Sunday, January 3, 2010 at 8:05amFirst, factor out the common 2x.

This leaves you with

2x[x^2 -6x +6) = 0

x=0 is one solution. The others are the two roots of

x^2 -6x +6 = 0,

which are not integers. You can compute them with the quadratic equation

x = [6 +/- sqrt(12)]/2 = 3 +/- sqrt3

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