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Posted by on Saturday, January 2, 2010 at 1:45pm.

How do I find all solutions in the interval [0,2Pi):


answer choices are:

b.) Pi/8, 5Pi/8, 9Pi/8, 13Pi/8

  • Trigonometry - , Saturday, January 2, 2010 at 2:24pm

    The solution is tan 2x = 1
    2x = arctan 1
    2x = pi/4 or (5/4) pi or (9/4) pi or (13 pi/8). You can ignore higher values because of the 2 pi limit on x.
    Solve for x

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