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A solution containing silver (I) ion (an oxidizing agent) is mixed with a solution containing iron (II) ion (a reducing agent).

a. What is the balanced equation?
b. If the contents of the reaction mixture described above are filtered, what substances, if any, would remain on the filter paper?


For A, I can't think of any other product other than AgFe, which makes no sense.

Help? Thanks!

  • chemistry - ,

    If silver (I) is the oxidizing agent, then it will gain an electron and become Ag (s)
    If Fe(II) is the reducing agent, then it loses an electron, and becomes Fe(III) ion.

  • chemistry - ,

    a. Ag+ + Fe2+ = Ag + Fe3+

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