posted by Coug on .
In a lab, .0092 moles of Cu were reacted with .0046 miles of S. What would happen to the mole Cu/mole S ratio if some of the copper was unreacted (increase, decrease, stay the same)?
Also, what will happen to the mole Cu/ Mole S ratio if unreacted sulfur remains in the crucible when the final weighing is made (increases, decreases, stays the same)?
Is the question about the mole ratio in the product or the mixture??
If the product is CuS, the mole ratio in the product is 1molCu/1molS=1 molCu/molS
The mole ratio of the masses of the elements in any compound is definite, not dependent on the reactants ratio in making it.