Posted by hrithik on .
can you explain me how to do this question. any help would be much appreciated.
1) If 0.025 mol of COCl2(g) is placed in a one liter container at 400c, 16.0% of the CoCl2 is dissociated when equilibrium is established.
COCl2(g)> Co(g)+Cl2(g)
calculate the value of K for the equilibrium at 400c.

chemistry 
DrBob222,
COCl2 ==> CO + Cl2
K = (CO)(Cl2)/(COCl2)
Start with 0.025 mol in a 1 L container makes it 0.025 molar in concentration.
16% dissociates; therefore, (CO) = 0.025 x 0.16 = ??. (Cl2) = 0.025 x 0.16 = ??
(COCl2) undissociated = 0.025 x 0.84 = ??.
Plug in the values and calculate K.