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Physics

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A weightlifter raises a 90k-g barbell from the floor to a height of 2/2 m in 0.6 s. What was his average power output during his lift?

Sorry I wrote it wrong the first time!

  • Physics - ,

    90k-g barbell from the floor to a height of 2.2 m in 0.6 s
    g=acceleration due to gravity=9.8 m/s^sup2;
    Work done
    =F.D
    = 90g * 2.2
    = 1940 N-m
    Power (W, N-m/s, or J/s)
    = 1940 J /0.6 s
    = 3234 W

    Note: one horsepower = 746 watts

  • Physics - ,

    M=90kg
    h=2.
    time=0.6sec
    g=9.8m/sec

    Power=w/t
    =f.h/t ( w=f.h)
    =m.g.h/t (f=m.g)
    =90×9.8×2/0.6
    =3234watt

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