McDonalds sells 6 times as many orders of French fries as Harry's Hamburger Hut every day. If both sold 60 more orders McDonalds would sell only 3 times as many fries. How many orders of fries do each sell before and after the increase?
Let x be the orders Harry sold
y be the orders McDonal sold
x + y = 60 (1)
and y/x = 3 (2)
s0lve this system x =15, y =45
after increase
H. sold 15+15 =30
Mc. sold 15*6 + 45 = 135
M = 6H
if each sold 60 more ...
M+60 = 3(H+60)
6H + 60 = 3H + 180
3H = 120
H = 40
M = 240
check: after increase
H = 100
M = 300
is 300 three times 100 ?
check!!
To solve this problem, let's assume the number of orders of French fries sold by Harry's Hamburger Hut is 'x' per day. Given that McDonald's sells 6 times as many orders of French fries as Harry's, the number of orders McDonald's sells can be represented as '6x'.
According to the problem, after both McDonald's and Harry's sell 60 more orders of fries, McDonald's will sell only 3 times as many as Harry's. So, the new number of orders McDonald's sells is '6x + 60', and the new number of orders Harry's sells is 'x + 60'.
Now, we can set up the equation based on the given information:
6x + 60 = 3(x + 60)
Expanding the equation:
6x + 60 = 3x + 180
Bringing all the 'x' terms to one side and the constant terms to the other side:
6x - 3x = 180 - 60
Simplifying:
3x = 120
Dividing both sides by 3:
x = 40
So, Harry's Hamburger Hut sells 40 orders of French fries before the increase, and McDonald's sells 6 times as many, which is 6 * 40 = 240 orders.
After the increase of 60 orders, Harry's Hamburger Hut sells 40 + 60 = 100 orders, and McDonald's sells 6 * (40 + 60) = 6 * 100 = 600 orders.
Therefore, both sell 40 and 240 orders of fries before the increase, and 100 and 600 orders of fries after the increase.