algebra
posted by Sarah .
Evaluate and simplify in a+bi form:
(6ã18))+(2+ã50)

ã radical

(6ã18))+(2+ã50)
= (6  √18) + (2 + √50)
=(6  3√2√1) + (2 + 5√2√1)
=(6  3√2 i) + (2 + 5√2 i)
= 8 + 2√2 i 
To show the squareroot sign (√), you can type:
"& r a d i c ;"
but omit the intervening spaces and the double quotes.
I assume you are asking to simplify:
(6√(18))+(2+&raidc;(50))
We first remove the outer parentheses and convert the radicals to i to get:
6√(18)+2+√(50)
8  √(18)i + √(50)i
= 8  3√2 i + 5√2 i
= 8 +2√2 i 
Isn't it same as 8+2i&radic2

The question asked for:
"Evaluate and simplify in a+bi form:"
In any case the "i" is usually put after the coefficient. √2 is considered part of the coefficient.