Posted by **Sarah** on Sunday, December 27, 2009 at 5:47pm.

Evaluate and simplify in a+bi form:

(6--18))+(2+-50)

- algebra -
**Sarah**, Sunday, December 27, 2009 at 5:48pm
- radical

- algebra -
**Reiny**, Sunday, December 27, 2009 at 5:58pm
(6--18))+(2+-50)

= (6 - √-18) + (2 + √-50)

=(6 - 3√2√-1) + (2 + 5√2√-1)

=(6 - 3√2 i) + (2 + 5√2 i)

= 8 + 2√2 i

- algebra -
**MathMate**, Sunday, December 27, 2009 at 6:02pm
To show the square-root sign (√), you can type:

"& r a d i c ;"

but omit the intervening spaces and the double quotes.

I assume you are asking to simplify:

(6-√(-18))+(2+&raidc;(-50))

We first remove the outer parentheses and convert the radicals to i to get:

6-√(-18)+2+√(-50)

8 - √(18)i + √(50)i

= 8 - 3√2 i + 5√2 i

= 8 +2√2 i

- algebra -
**Sarah**, Sunday, December 27, 2009 at 6:38pm
Isn't it same as 8+2i&radic2

- algebra -
**MathMate**, Sunday, December 27, 2009 at 7:03pm
The question asked for:

"Evaluate and simplify in **a+bi** form:"

In any case the "i" is usually put after the coefficient. √2 is considered part of the coefficient.

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