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Posted by on Sunday, December 27, 2009 at 5:47pm.

Evaluate and simplify in a+bi form:
(6-ã-18))+(2+ã-50)

  • algebra - , Sunday, December 27, 2009 at 5:48pm

    ã- radical

  • algebra - , Sunday, December 27, 2009 at 5:58pm

    (6-ã-18))+(2+ã-50)
    = (6 - √-18) + (2 + √-50)
    =(6 - 3√2√-1) + (2 + 5√2√-1)
    =(6 - 3√2 i) + (2 + 5√2 i)
    = 8 + 2√2 i

  • algebra - , Sunday, December 27, 2009 at 6:02pm

    To show the square-root sign (√), you can type:
    "& r a d i c ;"
    but omit the intervening spaces and the double quotes.

    I assume you are asking to simplify:
    (6-√(-18))+(2+&raidc;(-50))
    We first remove the outer parentheses and convert the radicals to i to get:
    6-√(-18)+2+√(-50)
    8 - √(18)i + √(50)i
    = 8 - 3√2 i + 5√2 i
    = 8 +2√2 i

  • algebra - , Sunday, December 27, 2009 at 6:38pm

    Isn't it same as 8+2i&radic2

  • algebra - , Sunday, December 27, 2009 at 7:03pm

    The question asked for:
    "Evaluate and simplify in a+bi form:"
    In any case the "i" is usually put after the coefficient. √2 is considered part of the coefficient.

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