Posted by Priscilla on Saturday, December 26, 2009 at 9:03am.
Ok i think i understand. I'm pretty sure you have to use the full equation d= vit +1/2 at^2
a) The average velocity when decelerating will be Vo/2 = 27.5 m/s. Multiply that by the time required to stop, Vo/a, to get the stopping distance X.
X = (Vo/a) * (Vo/2)
X = Vo^2/(2 a)= (55)^2/(22) = 137.5 m
Same answer you got, but I used a shortcut
HAPPY NEW YEAR! Ok, thanks a lot.
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