Friday

December 19, 2014

December 19, 2014

Posted by **Heart** on Friday, December 25, 2009 at 8:37pm.

GIVEN:

m = 0.145 kg

v = 42 m/s

batter v = 58 m/s

a. Find the change in momentum of the ball.

p = mv

p = (0.145)(42)

p = 6.09

--> What velocity would I use? Would i use the velocity of the baseball

b. If the ball and bat are in contact for 4.6 x 10^-4 s, what is the average force during contact?

- physics -
**drwls**, Friday, December 25, 2009 at 10:23pma) The sign of the velocity changes after the ball is hit. That makes the CHANGE in momentum equal to

M[42 -(-58)] = 0.145 kg * 100 m/s

b) Impulse

= (average force) x (time of contact)

= (change in momentum) = 14.5 kg m/s

Solve for the average force

**Answer this Question**

**Related Questions**

Physics - I got all but this problem. A 0.145-kg baseball is pitched at 42.0 m/...

Physice - I got all but this problem, I A 0.145-kg baseball is pitched at 42.0 m...

physics - A 0.145-kg baseball pitched horizontally at 27 m/s strikes a bat and ...

physics-momentum - A 0.145-kg baseball pitched horizontally at 39 m/s strikes a ...

physics for scientists and engeneers I - A 0.145-kg baseball pitched ...

Physics - Now assume that the pitcher in Part D throws a 0.145-kg baseball ...

college physics - Now assume that the pitcher throws a 0.145 kg baseball ...

physics - a .415 kg baseball is pitched at 42 m/s. the batter hits it ...

Physics - A 0.149-kg baseball is pitched a 40 m/s. The batter hits it ...

Physics w/ Calc - A baseball approaches home plate at a speed of 43.0 m/s, ...