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October 20, 2014

October 20, 2014

Posted by **Heart** on Friday, December 25, 2009 at 8:37pm.

GIVEN:

m = 0.145 kg

v = 42 m/s

batter v = 58 m/s

a. Find the change in momentum of the ball.

p = mv

p = (0.145)(42)

p = 6.09

--> What velocity would I use? Would i use the velocity of the baseball

b. If the ball and bat are in contact for 4.6 x 10^-4 s, what is the average force during contact?

- physics -
**drwls**, Friday, December 25, 2009 at 10:23pma) The sign of the velocity changes after the ball is hit. That makes the CHANGE in momentum equal to

M[42 -(-58)] = 0.145 kg * 100 m/s

b) Impulse

= (average force) x (time of contact)

= (change in momentum) = 14.5 kg m/s

Solve for the average force

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