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December 22, 2014

December 22, 2014

Posted by **CHIKIRSHU** on Friday, December 25, 2009 at 3:11am.

Q.2.The angle (in radians) made by the string of simple pendulum with the vertical depends on time as TEETHA = (pi/90)sin[(pi/sec)t].Find the length of the pendulum if g = (pi.pi) i.e. pi sqare meter per second sqare.

- PHYSICS -
**drwls**, Friday, December 25, 2009 at 5:42amQ1. A numerical value for the peiod cannot be provided without numerical values for the mass m and original spring constant, k. Before cutting aqnd rearranging, the period was

P1 = 2 pi sqrt (m/k)

After cutting, the two springs have sping constants 3k (short spring) and (3k/2) (long spring). When arranged in parallel, the spring constants add to give an effective spring constant of 9k/2. The new period is

P2 = 2 pi sqrt[(2/9)(m/k)]

= (sqrt2)/3 * P1

Q2. I don't understand the meaning of (pi/sec)t as the argument of the sin function.

If the angle argument is pi*t, with t in seconds, then sqrt(g/L) = w = pi (sec^-1)

where w is the angular frequency, which equals sqrt (g/L)

If g = pi^2 (m/s^2), then

g/L = pi^2 = pi^2/L

so L = 1 m

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