howmany ways can 8 people line up for play tickets?
Thank you
We would line them up one person at a time.
We have 8 choices for the first person. That makes 8 choices.
For the second person, we are left with 7 choices, together with the first, we have 8*7=56 ways.
For the third person, we are left with 6 people from whom to choose, so together there are 8*7*6 ways.
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For the last person, there is only 1 possible choice, so together we have 8*7*6*5*4*3*2*1 ways to make the line-up.
Calculate the number of ways the line-up can be made.
Thank you
THIS IS INCORRECT
To find the number of ways that 8 people can line up for play tickets, we can use the concept of permutations.
Permutations refer to the number of ways to arrange a set of objects in a particular order. In this case, we want to find the number of ways to arrange 8 people in a line.
The formula to calculate permutations is given by:
P(n, r) = n! / (n - r)!
Where:
n is the total number of objects in the set (in this case, the number of people)
r is the number of objects taken at a time (in this case, the number of people being lined up)
! denotes the factorial function, which means multiplying a number by all positive whole numbers below it
Using this formula, we have:
P(8, 8) = 8! / (8 - 8)!
P(8, 8) = 8! / 0!
Since 0! is equal to 1, the expression simplifies to:
P(8, 8) = 8!
Calculating 8! (8 factorial) means multiplying 8 by all the positive whole numbers below it:
8! = 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1
8! = 40,320
Therefore, there are 40,320 ways for 8 people to line up for play tickets.