Tuesday

January 17, 2017
Posted by **Anonymous** on Sunday, December 20, 2009 at 7:00pm.

- Math -
**Reiny**, Sunday, December 20, 2009 at 7:08pm3log10of(x-6)=11

log 10 (x-6)^3 = 11

(x-6)^3 = 10^11

x-6 = 10^(11/3)

x = 10^(11/3) + 6

for the second, let e^x = a

then we have

a^2 + 10a - 25 = 0

(a-5)^2 = 0

a = +- 5

e^x = 5 or e^x = -5 (the second has no solution)

x = ln5