Posted by Anonymous on Sunday, December 20, 2009 at 7:00pm.
3log10of(x-6)=11
log 10 (x-6)^3 = 11
(x-6)^3 = 10^11
x-6 = 10^(11/3)
x = 10^(11/3) + 6
for the second, let e^x = a
then we have
a^2 + 10a - 25 = 0
(a-5)^2 = 0
a = +- 5
e^x = 5 or e^x = -5 (the second has no solution)
x = ln5
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