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March 30, 2017

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ok i don't get this one

in 1920 the record for a certain race was 45.9 sec in 1980 it was 44.1 sec let r (T) = the record in the race and t= the number of years since 1920

(a) find a linear fuction that fits the data
(b) use the funcation in (a) to perdict the record for 2003 and 2006
(c) find t he year when the record will be 43.20 sec..

help please thatnks in advance

  • algebra - ,

    r = m (t) + b
    when year = 1920, t = 0
    where t = year - 1920
    45.9 = m (0) + b
    so b = 45.9
    44.1 = m (1980-1920) + 45.9
    44.1 = 60 m + 45.9
    60 m = -1.8
    m = -.03
    so
    r =-.03 t + 45.9
    when year = 2003
    t = 2003 - 1920 = 83
    r = -.03 (83) + 45.9
    r = 43.41
    that should get you started

  • algebra - ,

    so what yr will it be 43.20

  • algebra - ,

    so r(t)=?

  • algebra - ,

    as I said
    r =-.03 t + 45.9

    then
    43.2 = -.03 t + 45.9
    .03 t = 2.7
    t = 90
    1920 + 90 = 2010

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