algebra
posted by Rich on .
Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 60 miles per hour and train B is traveling at 80 miles per hour. Train A passes a station at 5:15 A.M. IF train B passes the same station at 5:27A.M., at what time will train B catch up to train A?

At 5:27 am, train B is behind train A by
(2715)/60*60 h*mph
= 12 mi
Train B's speed exceeds that of train A by
(8060)=20 mph.
Can you take it from here? 
A travels for time t
B travels for time (t  12 minutes )
A goes 60 mph = 1 mile/minute
B goes 80 mph = 4/3 mile/minute
distance is the same
so
1 t = (4/3)(t12)
3 t = 4 t  48
t = 48 minutes
5:15 + 48 minutes = 5:63 which is 6:03