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April 18, 2014

April 18, 2014

Posted by **Rich** on Sunday, December 20, 2009 at 2:38pm.

- algebra -
**MathMate**, Sunday, December 20, 2009 at 4:01pmAt 5:27 am, train B is behind train A by

(27-15)/60*60 h*mph

= 12 mi

Train B's speed exceeds that of train A by

(80-60)=20 mph.

Can you take it from here?

- algebra -
**Damon**, Sunday, December 20, 2009 at 4:04pmA travels for time t

B travels for time (t - 12 minutes )

A goes 60 mph = 1 mile/minute

B goes 80 mph = 4/3 mile/minute

distance is the same

so

1 t = (4/3)(t-12)

3 t = 4 t - 48

t = 48 minutes

5:15 + 48 minutes = 5:63 which is 6:03

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