Posted by **Karen** on Sunday, December 20, 2009 at 2:16pm.

The width of a rectangle is fixed at 19 cm. What lengths will make the perimeter greater than 82 cm. The length must be greater than ___ cm

- Algebra -
**Marth**, Sunday, December 20, 2009 at 2:23pm
The perimeter of a rectangle is given by P = 2(L + W). We want P > 82cm with width fixed at 19cm.

2(L + 19) > 82

Solve for L.

- Algebra -
**MathMate**, Sunday, December 20, 2009 at 2:24pm
Start with perimeter = 2(W+L)

If W=19, and perimeter > 82, we end up with the inequality:

2(19+L) > 82

Solve for L to get the answer.

- Algebra -
**timtyy**, Thursday, January 21, 2010 at 7:41pm
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