Posted by Karen on .
The width of a rectangle is fixed at 19 cm. What lengths will make the perimeter greater than 82 cm. The length must be greater than ___ cm

Algebra 
Marth,
The perimeter of a rectangle is given by P = 2(L + W). We want P > 82cm with width fixed at 19cm.
2(L + 19) > 82
Solve for L. 
Algebra 
MathMate,
Start with perimeter = 2(W+L)
If W=19, and perimeter > 82, we end up with the inequality:
2(19+L) > 82
Solve for L to get the answer. 
Algebra 
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