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January 28, 2015

January 28, 2015

Posted by **mike** on Friday, December 18, 2009 at 7:17pm.

x+y+z=7,x-y+2z=7,2x+y+3z=15

The final answer came out to be

x=4

z=2

y=1

- Algebra Question -
**Reiny**, Friday, December 18, 2009 at 11:36pmThis problem just "begs" to be done by elimination, look at the y values

add #1 and #2 2x + 3z = 14 #4

add #2 and #3 3x + 5z = 22 #5

triple #4 -- 6x + 9z = 42

double #5 -- 6x + 10z = 44

subtract #5 - #4

z = 2

sub into #4 -- 2x+6 = 14 , x = 4

back into #1

4 + y + 2 = 7

y = 1

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