Posted by mike on Friday, December 18, 2009 at 6:40am.
What am I doing wrong I am using the Gauss Jordan method to calculate this answer and some other students are coming up with differant answers.
Problem is
3x+y+z=5,
x+5yz=8,
10x+7y+z=2
My answer is (6z+3,7z4
_________, z
( 11 11)
Where I have +3 they have +33 and where I have 4 they have 44 Can you let me know how they came up with the larger numbers

Algebra Question  bobpursley, Friday, December 18, 2009 at 9:32am
This does not make sense to me. You have three equations, three unknowns. YOu can solve for x,y,z. Whatever you are doing, I don't understand.

Algebra Question  mike, Friday, December 18, 2009 at 10:58am
What am I doing wrong I am using the Gauss Jordan method to calculate this answer and some other students are coming up with differant answers.
Problem is
3x+y+z=5,
x+5yz=8,
10x+7y+z=2
Answers are
1(6z+3/11, 7z4/11,z)
2(6z+33/11,7z44/11)
I got #1 for my answer and some got #2 which one is right. Some got all kinds of numbers. 
Algebra Question  bobpursley, Friday, December 18, 2009 at 11:06am
well, I didn't get anything like that, I got a specific number solution for x, y, and z.
When you say "calculate" and answer, that to me implies looking for a specific solution.
Here is a Gauss Jordan applet, check your work
http://www.gregthatcher.com/Mathematics/GaussJordan.aspx 
Algebra Question  mike, Friday, December 18, 2009 at 11:13am
My mistake New at this Question should be Use the GaussJordn method to solve the system of equations.

Algebra Question  bobpursley, Friday, December 18, 2009 at 11:20am
well, both your 1) and 2) are NOT solutions. Solutions have specific values for x,y, and z.