Thursday

January 19, 2017
Posted by **mike** on Friday, December 18, 2009 at 6:40am.

Problem is

3x+y+z=5,

x+5y-z=-8,

10x+7y+z=2

My answer is (-6z+3,7z-4

_________, z

( 11 11)

Where I have +3 they have +33 and where I have -4 they have -44 Can you let me know how they came up with the larger numbers

- Algebra Question -
**bobpursley**, Friday, December 18, 2009 at 9:32amThis does not make sense to me. You have three equations, three unknowns. YOu can solve for x,y,z. Whatever you are doing, I don't understand.

- Algebra Question -
**mike**, Friday, December 18, 2009 at 10:58amWhat am I doing wrong I am using the Gauss Jordan method to calculate this answer and some other students are coming up with differant answers.

Problem is

3x+y+z=5,

x+5y-z=-8,

10x+7y+z=2

Answers are

1-(-6z+3/11, 7z-4/11,z)

2-(-6z+33/11,7z-44/11)

I got #1 for my answer and some got #2 which one is right. Some got all kinds of numbers. - Algebra Question -
**bobpursley**, Friday, December 18, 2009 at 11:06amwell, I didn't get anything like that, I got a specific number solution for x, y, and z.

When you say "calculate" and answer, that to me implies looking for a specific solution.

Here is a Gauss Jordan applet, check your work

http://www.gregthatcher.com/Mathematics/GaussJordan.aspx - Algebra Question -
**mike**, Friday, December 18, 2009 at 11:13amMy mistake New at this Question should be Use the Gauss-Jordn method to solve the system of equations.

- Algebra Question -
**bobpursley**, Friday, December 18, 2009 at 11:20amwell, both your 1) and 2) are NOT solutions. Solutions have specific values for x,y, and z.