Find the equation of a line that passes through the point (1,2) and has a slope of 1/3
Can you please show me how you found the equation.
y= slope*x+ intercept
y= 1/3 x + intercept
put in x,y and solve for intercept, and you have it.
Very helpful! Thank you!
To find the equation of a line given a point and the slope, you can use the point-slope form of the equation: y - y1 = m(x - x1), where (x1, y1) represents the given point and m represents the slope.
In this case, the given point is (1, 2), and the slope is 1/3. Plugging these values into the point-slope form, we have:
y - 2 = (1/3)(x - 1)
Now, we can simplify the equation by distributing the slope:
y - 2 = (1/3)x - 1/3
Next, we can get rid of the fraction by multiplying every term in the equation by 3:
3(y - 2) = 3(1/3)x - 3(1/3)
This simplifies to:
3y - 6 = x - 1
Now, let's rearrange the equation to get the standard form (Ax + By = C):
x - 3y = -5
Therefore, the equation of the line that passes through the point (1, 2) and has a slope of 1/3 is x - 3y = -5.