What is the y-component of a 95.3-N force that is exerted at 57.1 degrees to the horizontal?
Forcey= 95.3*Sin57.1
What is the y-component of a 95.3 N force that is exerted at 57.1o to the horizontal
What is the y-component of a 95.3 N force that is exerted at 57.1° to the horizontal?
What is the x-component of a 95.3-N force that is exerted at 57.1° to the horizontal?
What is the y- component of a 93.5 N force
that exert at 57.10 to the horizontal?
What is the y- component of a 93.5 N force
that exert at 57.10 to the horizontal?
To find the y-component of a force, you can use trigonometry. The y-component is the vertical component of the force.
First, let's represent the given information in a diagram. Draw a coordinate system where the x-axis represents the horizontal direction and the y-axis represents the vertical direction.
The force has a magnitude of 95.3 N and is exerted at an angle of 57.1 degrees to the horizontal.
Next, we can use the trigonometric functions sine and cosine to find the x and y-components of the force.
The x-component is given by:
Fx = F * cos(θ)
The y-component is given by:
Fy = F * sin(θ)
Where F is the magnitude of the force and θ is the angle it makes with the horizontal.
Plugging in the values we have:
Fx = 95.3 N * cos(57.1°)
Fy = 95.3 N * sin(57.1°)
Now, we just need to calculate these values.
Using a calculator, calculate:
Fx = 95.3 N * cos(57.1°) = 53.165 N
Fy = 95.3 N * sin(57.1°) = 79.433 N
Therefore, the y-component of the 95.3 N force is approximately 79.433 N.