Friday

December 19, 2014

December 19, 2014

Posted by **Stuck** on Tuesday, December 15, 2009 at 12:27am.

- Math -
**Reiny**, Tuesday, December 15, 2009 at 8:05amWhat we don't want is a selection with no face cards or red cards.

If we take all the reds and facecards out, there would be 30 cards left.

so if we find the prob of getting 2 of those cards

= 30/52 x 29/51 = 145/442

So the prob of the stated problem = 1 - 145/442 = 297/442

- Check that - Math -
**Reiny**, Tuesday, December 15, 2009 at 9:20amI misread your question.

It is actually easier than the one I answered.

Since there are 22 cards that are either red or face cards in the deck, the prob(red or face) on the first draw = 22/52 = 11/26

(Why are you stating that there are 2 cards drawn, and why are you stating replacement conditions, if all you are interested in is the first card?)

- Math -
**Stuck**, Tuesday, December 15, 2009 at 11:04pmThank you! I understand now. The probability is actually 8/13, but you definitely had the right idea. Thanks again!

**Answer this Question**

**Related Questions**

Math - A card is selected from a standard deck of 52 playing cards. A standard ...

College Math - A card is selected from a standard deck of 52 playing cards. A ...

Math - A card is selected from a standard deck of 52 playing cards. A standard ...

geometry - A card is selected from a standard deck of 52 playing cards. A ...

stats math - Suppose that two cards are randomly selected from a standard 52-...

math - One card is selected at random from a standard 52-card deck of playing ...

Stats - Suppose you have a standard deck 52 cards (4 suits: hearts, diamonds, ...

Math - Two cards are drawn in succession without replacement from a standard ...

MATH!! probability - Two cards are drawn without replacement from a deck of 52 ...

math - Two cards are drawn without replacement from an ordinary deck of 52 cards...