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April 18, 2015

April 18, 2015

Posted by **Stuck** on Tuesday, December 15, 2009 at 12:27am.

- Math -
**Reiny**, Tuesday, December 15, 2009 at 8:05amWhat we don't want is a selection with no face cards or red cards.

If we take all the reds and facecards out, there would be 30 cards left.

so if we find the prob of getting 2 of those cards

= 30/52 x 29/51 = 145/442

So the prob of the stated problem = 1 - 145/442 = 297/442

- Check that - Math -
**Reiny**, Tuesday, December 15, 2009 at 9:20amI misread your question.

It is actually easier than the one I answered.

Since there are 22 cards that are either red or face cards in the deck, the prob(red or face) on the first draw = 22/52 = 11/26

(Why are you stating that there are 2 cards drawn, and why are you stating replacement conditions, if all you are interested in is the first card?)

- Math -
**Stuck**, Tuesday, December 15, 2009 at 11:04pmThank you! I understand now. The probability is actually 8/13, but you definitely had the right idea. Thanks again!

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