Posted by jj on .
A chair of weight 150 lies atop a horizontal floor; the floor is not frictionless. You push on the chair with a force of = 36.0 directed at an angle of 40.0 below the horizontal and the chair slides along the floor.Using Newton's laws, calculate , the magnitude of the normal force that the floor exerts on the chair
Fx= 36cos40 in hor direction
Fy= 36sin40 in vertical downward direction
For equilibrium in vertical direction
Normal Force N=mg+Fy