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December 21, 2014

December 21, 2014

Posted by **Salman** on Monday, December 14, 2009 at 4:15pm.

INT (x)/(sqrt(-191-8x^2+80x))dx

x=?

- Calculus -
**MathMate**, Monday, December 14, 2009 at 11:28pmThe integral will be of the form

(y+5)/sqrt(a^2-y^2)

if you complete the square of the expression under the square-root sign using

y=x-5, or x=y-5

That will reduce the given integral to two simpler ones.

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