Posted by Amber on .
waht is the slope of the normal line to y^2 = x/2 at P(1/8,1/4)??

math 
MathMate,
Janice, Nadine, Elmo, Keisha and Amber, you're probably working together one way or another. So you can also help each other.
As before, use implicit differentiation to get y':
2yy'=(1/2)
y'=(1/2)/(2y)
The slope of the normal is given by
m=1/y'=4y
So the line for the normal is
L1: (yy1)=m(xx1)