Posted by **Amber** on Monday, December 14, 2009 at 9:05am.

waht is the slope of the normal line to y^2 = x/2 at P(1/8,1/4)??

- math -
**MathMate**, Monday, December 14, 2009 at 9:36am
Janice, Nadine, Elmo, Keisha and Amber, you're probably working together one way or another. So you can also help each other.

As before, use implicit differentiation to get y':

2yy'=(1/2)

y'=(1/2)/(2y)

The slope of the normal is given by

m=-1/y'=-4y

So the line for the normal is

L1: (y-y1)=m(x-x1)

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