Posted by **Ian** on Monday, December 14, 2009 at 8:44am.

In a hydraulic lift, if the radius of the smaller piston is 2 cm and the radius of the larger piston is 20 cm, what weight can the larger piston support when a force of 250 N is applied to the smaller piston?

d = diameter of smaller piston

D = diameter of larger piston

I just have to use the formula

[(250 N)(pi*d^2/4)] / (pi*D^2/4)

is this correct??

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