Physics
posted by Ian on .
In a hydraulic lift, if the radius of the smaller piston is 2 cm and the radius of the larger piston is 20 cm, what weight can the larger piston support when a force of 250 N is applied to the smaller piston?
d = diameter of smaller piston
D = diameter of larger piston
I just have to use the formula
[(250 N)(pi*d^2/4)] / (pi*D^2/4)
is this correct??

the pressure in each side is the same.
F1/Area1=Force2/area2
Flarger=arealarger*250N/PI*.02^2 in N
= .1^2/.02^2 *250N = 25*250N
check my thinking.