Post a New Question

Physics

posted by on .

In a hydraulic lift, if the radius of the smaller piston is 2 cm and the radius of the larger piston is 20 cm, what weight can the larger piston support when a force of 250 N is applied to the smaller piston?

d = diameter of smaller piston
D = diameter of larger piston
I just have to use the formula
[(250 N)(pi*d^2/4)] / (pi*D^2/4)

is this correct??

  • Physics - ,

    the pressure in each side is the same.

    F1/Area1=Force2/area2

    Flarger=arealarger*250N/PI*.02^2 in N
    = .1^2/.02^2 *250N = 25*250N
    check my thinking.

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question