Homework Help: Physics

Posted by Ian on Monday, December 14, 2009 at 8:44am.

In a hydraulic lift, if the radius of the smaller piston is 2 cm and the radius of the larger piston is 20 cm, what weight can the larger piston support when a force of 250 N is applied to the smaller piston?

d = diameter of smaller piston
D = diameter of larger piston
I just have to use the formula
[(250 N)(pi*d^2/4)] / (pi*D^2/4)

is this correct??

Physics - bobpursley, Monday, December 14, 2009 at 9:09am
the pressure in each side is the same.

F1/Area1=Force2/area2

Flarger=arealarger*250N/PI*.02^2 in N
= .1^2/.02^2 *250N = 25*250N
check my thinking.

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