Posted by sh on Sunday, December 13, 2009 at 9:56pm.
The zeros of the derivative or the zeros of the function ?
I will assume you want the zeros of the derivative.
factor it first
= x^2(x-1)^3[4x + 3(x-1)]
= x^2(x-1)^3(7x-3)
we set this equal to zero to get
x = 0, x = 1 and x = 3/7
remember that the function increases when the first derivative is positive, and decreases when that derivative is negative.
Can you take it from here ?
Do you factor it by taking the lowest ^ ? I can continue from there, thanks! :)
The answer key indicated that 0 is not a zero.
Your question was,
"how do I find the zeros"
x = 0 is a solution to h(x) = 0 and h'(x) = 0
If x=0, shouldn't it be used to determine the increase and decrease?
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