Homework Help: Math

Posted by Anonymous on Sunday, December 13, 2009 at 4:36pm.

Find the area of a triangle with a base of 3 5/8 in. and a height of 2 1/2 in.

A)4 15/32 in 2 (sq)

B)8 1/16 in 2 (sq)

C)4 17/32 in 2 (sq)

D)8 17/32 in 2 (sq)

Help!! I am so confused.

Math - MathMate, Sunday, December 13, 2009 at 7:04pm
Area of triangle = (1/2)base*height
here we need to convert the mixed numbers (i.e. sum of number and fractions) to improper fractions (numerator is greater than the denominator) to facilitate the eventual multiplication:

base = 3 5/8 in. = (8*3+5)/8" = 29/8"
height = 2 1/2 in. =(2*2+1)/2" = 5/2"

Now calculate the area
A = (1/2)*(29/8)*(5/2)
=145/32 sq.in.

Convert the improper fraction into a mixed number and make your choice of the answers.

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