Posted by M B on Sunday, December 13, 2009 at 11:46am.
2Al + Fe2O3 ==>2Fe and Al2O3 + ??kJ heat.
Do you know the kJ heat produced? If so,
313 kJ/?? kJ = moles Fe2O3 needed and convert that to grams Fe2O3.
(313 kJ/?? kJ) x 2 = moles Al needed and convert that to grams Al.
Add the grams Fe2O3 and grams Al to get the grams of the mixture needed.
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