Posted by mike on Sunday, December 13, 2009 at 7:38am.
Let the number of long-sleeve blouses be x
let the number of short-sleeve blouses be y
let the number of sleeveless blouses by z
I see two equations
1.5x + y + .5z = 380
3x + 2y + z = 760 (#1)
1.2x + .9y + .6z = 330 ----> (times 10/3)
4x + 3y + 2z = 1100 (#2)
I doubled the first, then subtracted the second to get
2x + y = 420
or y = 420 - 2x, where 0 ≤ x ≤ 210
and form #1
z = 760 - 3x - 2y , where z > 0
Making a chart of ordered triplets, it is clear that there are many different triplets that are possible for full capacity.
e.g. (150,120,70) , (80,260,0) , (210,0,130) all work.
Are you sure there wasn't a restraint based on the profit of each of the products?
There was nothing. I gave the whole problem. I did some problems earlier and was ok We never studeied this type of problem and I get confused when new shows up.