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July 1, 2015

July 1, 2015

Posted by **mike** on Sunday, December 13, 2009 at 7:38am.

- Algebra Word Problems -
**Reiny**, Sunday, December 13, 2009 at 9:30amLet the number of long-sleeve blouses be x

let the number of short-sleeve blouses be y

let the number of sleeveless blouses by z

I see two equations

1.5x + y + .5z = 380

3x + 2y + z = 760 (#1)

1.2x + .9y + .6z = 330 ----> (times 10/3)

4x + 3y + 2z = 1100 (#2)

I doubled the first, then subtracted the second to get

2x + y = 420

or y = 420 - 2x, where 0 ≤ x ≤ 210

and form #1

z = 760 - 3x - 2y , where z > 0

Making a chart of ordered triplets, it is clear that there are many different triplets that are possible for full capacity.

e.g. (150,120,70) , (80,260,0) , (210,0,130) all work.

Are you sure there wasn't a restraint based on the profit of each of the products?

- Algebra Word Problems -
**mike**, Sunday, December 13, 2009 at 9:36amThere was nothing. I gave the whole problem. I did some problems earlier and was ok We never studeied this type of problem and I get confused when new shows up.