Posted by k on Saturday, December 12, 2009 at 6:54pm.
In falling freely 1.7 m, both climbers reach a velocity of sqrt(2g*1.7) = 5.77 m/s and a kinetic energy M g *1.7
The average force needed to stop in a distance is given by
F = KE/X = 1.7Mg/X
That is 1.7/1 = 1.7 times the body weight for Karen and 1.7/0.25 = 6.8 times the body weight of Bill
How would you answer the last question?
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