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March 2, 2015

March 2, 2015

Posted by **Anonymous** on Saturday, December 12, 2009 at 5:39pm.

the building and measured an angle of 38 degrees to the top of the building. He then

walked 100 feet further away from the building and measured an angle of 34 degrees to

the top.

How tall is the building?

I know I'm suppose to use tan

I got tan38=y/x from the first part of the information. I need help getting the second part

- Math -
**Reiny**, Saturday, December 12, 2009 at 7:04pmfrom the outer triangle

tan 34 = y/(x+100)

y = (x+100)tan 34

from your equation

y = xtan 38

so xtan 38 = (x+100)tan 34

xtan 38 = xtan 34 + 100tan 34

xtan 38 - xtan 34 = 100tan 34

x(tan 38 - tan 34) = 100tan 34

x = 100tan 34/(tan 38 - tan 34)

once you found x, you can find y using your first equation.

- Math -
**unique**, Monday, January 12, 2015 at 8:32pmyou should help me mines is kinda like that and i dont understand it

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