Posted by **Anonymous** on Saturday, December 12, 2009 at 3:54pm.

A toy car runed off the edge of a table that is 1.225m high. If the car lands 0.400m from the base of the car to fall,

a)how long does it take the car to fall

2(1.225)/-9.80=-0.25=0.5s

b)what is the horizontal velocity of the car?

- physics -
**drwls**, Saturday, December 12, 2009 at 4:07pm
Actually, the time to fall is

T = sqrt (2H/g).

That seems to be what you did, but you were incorrect in writing

-0.25 = .50

Also since you are measuring distance down, forget the minus sign.

Once you get the time T, use

T = D/Vx to get the horizontal velocity, Vx.

- physics -
**Anonymous**, Monday, September 8, 2014 at 12:17pm
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