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physics

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A steel ball rolls with constant velocity across a tabletop 0.950m high. IT rolls off and hits the ground +0.352m horizontally from the edge of the table. How fast was the ball rolling?

  • physics - ,

    Get the time to fall from the height, H = 0.950 m. Call that time T. You will need to use the acceleration of gravity (g) to compute T.
    H = (g/2) T^2
    Haven't you seen that equation before for falling bodies?

    Then use the relationship
    V T = 0.352
    to get V

  • physics - ,

    A steel ball rolls with constant velocity across a tabletop 0.950m high. IT rolls off and hits the ground +0.352m horizontally from the edge of the table. How fast was the ball rolling?

    GIVEN:

    Vi = 0 m/s
    d = 0.950 m ---> 0.352 m
    a = 9.81 m/s^2
    t = ?

    d = Vit + 1/2 at^2

    0.352 = 1/2 (9.82 m/s^2) (t)^2

    0.352 = 4.905t^2

    --> Divide by 4.095

    square root - 0.071763507 = t^2

    0.26 s = t

  • physics - ,

    1.35 m/s

  • physics - ,

    8.0

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