Posted by Rafael Alvarez on .
Identify the limiting reactant and determine the mass of the excess reactant remaining when 7.00 g of chlorine gas reacts with 5.00 g of potassium to form potassium chloride.
2molK + 1molClgas create 2molKCl
so Cl gas excess
mClgas(excess) = 7-(5*71/78) = 2.45g