Posted by Kelly on Friday, December 11, 2009 at 4:00am.
They don't tell you the angle (measured above horizontal) that the ball was thrown, but you can figure it out.
For a ball thrown horizontally, the distance fallen (vertically) is
Y = (g/2) t^2 = 17.9 m
Since that is also the height of the building, it WAS thrown horizontally. The horizontal velcoity component remains 23.9 m/s
Just multiply the initial velocity by the time of flight, to get the horizontal displacement.
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