A dolphin jumps with an initial velocity of 10.5 m/s at an angle of 32.0° above the horizontal. The dolphin passes through the center of a hoop before returning to the water. If the dolphin is moving horizontally when it goes through the hoop, how high above the water is the center of the hoop in meters?
physics - drwls, Friday, December 11, 2009 at 1:12am
The time that the dolphin is in the air is 2*Vo sin32/g = 1.134 s. It rises for half of that time (0.567 s), and descends for the other half. The distance it rises is the average vertical velocity times the time going up or down, which is
H = (1/2)(Vo sin 32)*(Vo sin32/g)
(1/2)(Vo sin 32)^2/g
physics - Anonymous, Wednesday, November 6, 2013 at 1:18pm