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April 16, 2014

April 16, 2014

Posted by **Tom** on Thursday, December 10, 2009 at 11:52pm.

- physics -
**drwls**, Friday, December 11, 2009 at 1:12amThe time that the dolphin is in the air is 2*Vo sin32/g = 1.134 s. It rises for half of that time (0.567 s), and descends for the other half. The distance it rises is the average vertical velocity times the time going up or down, which is

H = (1/2)(Vo sin 32)*(Vo sin32/g)

(1/2)(Vo sin 32)^2/g

- physics -
**Anonymous**, Wednesday, November 6, 2013 at 1:18pmyes

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