a rectangle with measurements of length of 11, width of 4, diagonal of 11.7, area of 44 and perimeter of 30 needs to be increased by 20% and decreased by 20%. How do I get the new dimensions?

PLenty of redundant information, except the critical question is not clear.

Is the area to be increased by 20% or are the dimensions to be increased by 20%

Is the new rectangle similar to the old one?

RAYMOND HAS EXACTLY 360 SQUARE INCHES HE WANTS 2 DIMENSONS TO BE 6. HOW MANY DIFFERNET SIZES CAN HE MAKE

To find the new dimensions of the rectangle after increasing and decreasing it by 20%, you will follow these steps:

Step 1: Determine the current measurements of the rectangle:
- Length = 11
- Width = 4
- Diagonal = 11.7
- Area = 44
- Perimeter = 30

Step 2: Calculate the new length and width after increasing the rectangle's dimensions by 20%:
- Increase the length by 20%: 11 + (11 * 0.20) = 11 + 2.2 = 13.2
- Increase the width by 20%: 4 + (4 * 0.20) = 4 + 0.8 = 4.8

Step 3: Calculate the new length and width after decreasing the rectangle's dimensions by 20%:
- Decrease the length by 20%: 11 - (11 * 0.20) = 11 - 2.2 = 8.8
- Decrease the width by 20%: 4 - (4 * 0.20) = 4 - 0.8 = 3.2

Therefore, the new dimensions of the rectangle after increasing by 20% would be:
- Length = 13.2
- Width = 4.8

And the new dimensions of the rectangle after decreasing by 20% would be:
- Length = 8.8
- Width = 3.2