February 25, 2017

Homework Help: Trigonometry

Posted by Delia on Thursday, December 10, 2009 at 9:47pm.

I'm trying to find the cosecant of 11 pi/6. The answer is -2, but I'm not sure where this came from. I thought You would flip the sine value which was sq. root of 3/2, making it 2/sq. root of three, which would then become sq. root of -6 over 3 or sq. root of -2. Why isn't there a sq. root sign? Thanks!!!

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