posted by Cory on .
A vertical spring (k = 1040 N/m) is compressed a distance of 11.6 cm. A 47.9 g mass is placed on the spring, then released so the mass flies upward. When the mass is 120 cm above the spring, what is the speed of the mass?
Let Y be the elevation from the compressed position. When released and after reaching elevation Y = 0.12 m, the kinetic energy is the initial spring potential energy minus the gain ib gravitational potential energy.
KE = (PE)spring - (PE)gravity
(1/2)(0.0479 kg)V^2 = (1/2)k(0.116m)^2 - (0.0479)(9.8 m/s^2)(0.12 m)
Solve for V