Posted by **fko** on Thursday, December 10, 2009 at 4:38pm.

Mr. Digit wanted to assign a number to each student in his class. He could only use the digits 2,3,and 6 and each student's number had to have three digits. Can he find enough numbers for all 25 students if repeated digits are allowed? Will there be any extra numbers?

- Math -
**Ms. Sue**, Thursday, December 10, 2009 at 4:44pm
There may be a shortcut to finding this answer -- but you can do it this way:

222

223

226

232

233

236

262

263

266

Do the same with numbers beginning with 3 and 6.

- Math -
**Chrissy**, Thursday, December 10, 2009 at 4:45pm
Or you could just count how many numbers Ms. Sue provided and multiply by three for your total number of possiblities.

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