A 60.0-g sample of NaOH is dissolved in water, and the solution is diluted to give a final volume of 1.50 L. The molarity of the final solution is ?

Molarity=moles/volumeinLiters=60/(40*1.5)

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You need to memorize this definitiona.

To find the molarity of the final solution, we need to use the formula:

Molarity (M) = moles of solute / volume of solution in liters

First, let's calculate the moles of NaOH using its molar mass:

Molar mass of NaOH = 22.99 g/mol (atomic mass of Na) + 16.00 g/mol (atomic mass of O) + 1.01 g/mol (atomic mass of H)
= 39.99 g/mol

moles of NaOH = mass of NaOH / molar mass of NaOH
= 60.0 g / 39.99 g/mol

Next, we need to determine the volume of the solution in liters. The problem states that the final volume is 1.50 L.

Now we can substitute these values into the formula:

Molarity (M) = moles of NaOH / volume of solution in liters
= (60.0 g / 39.99 g/mol) / 1.50 L

Calculating this:

Molarity (M) ≈ 2.00 M (rounded to two decimal places)

Therefore, the molarity of the final solution is approximately 2.00 M.