Wednesday

January 28, 2015

January 28, 2015

Posted by **anonymous** on Wednesday, December 9, 2009 at 9:16pm.

Suppose you have 132 m of fencing with which to make two side-by-side rectangular enclosures against an existing wall. if the rectangular enclosures are adjacent and of the same depth what is the maximum are that can be enclosed?

- MATH ANALYSIS -
**MathMate**, Thursday, December 10, 2009 at 12:10amDraw a diagram!

You will need three cross fences, and one that is parallel to the wall.

Let the length of each cross fence be x.

Express the length L of the longitudinal fence in terms of x and 132 m.

Express the total area A(x) of the two rectangular areas in x and L, and subsequently in x only.

Use calculus to maximize A(x). Solve for x.

**Answer this Question**

**Related Questions**

MATH ANALYSIS - How should this be done? Suppose you have 132 m of fencing with ...

advanced math - Suppose you have 168 meters of fencing with which to make two ...

math - a farmer has 120 m of fencing to make two identical rectangular ...

Pre Calculus - He needs two adjacent rectangular enclosures - he has 300 feet of...

Calculus - A farmer has 120 meters of wire fencing to make enclosures for his ...

math - 1) A rancher wants to enclose two rectangular areas near a river, one for...

math - 1) A rancher wants to enclose two rectangular areas near a river, one for...

word problem? - A rectangular lot is to be bounded by a fence on three sides adn...

Math - if you have 200 feet of fencing to enclose four adjacent rectangular ...

optimization - A farmer wants to make 9 identical rectangular enclosures as ...