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11th grade

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A child sitting 1.08 m from the center of a merry-go-round moves with a speed of 1.20 m/s.
(a) Calculate the centripetal acceleration of the child.

  • 11th grade - ,

    see other post

  • 11th grade - ,

    centripetal acceleration is v^2/r where v is velocity and r is radius. so, 1.20^2/1.08 which is 1.33

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