Posted by Kay on Wednesday, December 9, 2009 at 7:30am.
1n(1+x) has Taylor series expansion
x - x^2/2 + x^3/3 + ...
Divide that by x and you get
1 - x/2 + x/3 + ...
The limit as x-> 0 is 1
You could also use L'Hopital's rule for x-> 0. The same rule applies at any singularity (0/0 or infinity/infinity).
I forgot about that expansion method. Will have to look it up. Thanks!
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