Homework Help: physics

Posted by kh on Wednesday, December 9, 2009 at 1:33am.

Two events in S are separated by a distance D=x2 - x1 and a time T = t2 - t1 .
a) Use the Lorenrz transformation to show that in frame S' , which is moving with speed v relative to S, the time separation is t2 - t1 = ă(T - vD/c2 ).
b) Show that the events can be simultaneous in frame S' only if D is greater than cT.
c) If one of the events is the cause of the other, the separation D must be less than cT since D/c is the smallest time that a signal can take to travel from x1 to x2 in frame S. Show tht if D is less than cT, t2' is greater than t1' in all refence frames. d) Suppose that a signal could be sent with speed c'>c so that in frame S the cause precedes the effect by the time T=D/c'. Show that there is then a reference frame moving with speed v less than c in which the effect precedes the cause.

No one has answered this question yet.

Answer this Question

Related Questions

physics - Two events in S are separated by a distance D=x2 - x1 and a time T = ...
Physics - Starting with the kinematics equation x = vot + ½ at^2, derive ...
Physics - What is the equation for average velocity given x1 (initial distance...
art - two vectors x1 = (20 m) x and x2 (15 m) x, compute and show graphically (a...
????Math Question????8th grade adv.math - Algebra! How is the distance formula ...
Math - Starting with the kinematics equation x = vot + ½ at^2, derive an ...
Algebra HELP! - Starting with the kinematics equation x = vot + ½ at^2, ...
Calculus (Urgent!!) - Hello everyone, I need help with the following problems. ...
Calculus - Find the partial derivative y with respect to s for the following ...
intro to probability - In a study of particulate pollution in air samples over a...

For Further Reading

First Name:
School Subject:
Answer: