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November 27, 2014

November 27, 2014

Posted by **Nancy** on Wednesday, December 9, 2009 at 12:50am.

H= 1600-1/2t^2

thats what i got as a function is that correct cause it doesnt work to get the final answer on how long it would take the rock to hit the floor.

- Calculus -
**drwls**, Wednesday, December 9, 2009 at 12:56amYou forgot the acceleration of gravity before the t^2

H = Ho - (1/2)gt^2 = 1600 -(9.8/2)t^2

Set that equal to 0 and solve for t.

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