Tuesday

March 31, 2015

March 31, 2015

Posted by **Nancy** on Tuesday, December 8, 2009 at 11:43pm.

i need the formula cause the one i have doesnt work cause i need time

- Calculus -
**Reiny**, Wednesday, December 9, 2009 at 12:11amvel = at where t is in hrs, and a is in miles/hrs^2

then s = (1/2)at^2 where s is the distance in miles

when v = 160

at=160

t = 160/a

when s= .7

(1/2)a(160/a)^2 = .7

a = 18285.7 miles/hrs^2

so what time is liftoff?

160 = 18285t

t = .00875 hrs or 31.5 seconds

check:

at t= 0,

v = 0

s = 0

when t = .00875

v = 18285.7(.00875) = 160

s = (1/2)(18285.7)(.00875)^2 = .699999

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