Sunday

April 20, 2014

April 20, 2014

Posted by **Clair** on Tuesday, December 8, 2009 at 11:38pm.

I have a test on this tomorrow.

For example: 3x^2 +1x - 2

How would I find the vertex in this?

- Math -
**Reiny**, Tuesday, December 8, 2009 at 11:49pmUnless you are instructed to do it in a certain way, here is the simplest and quickest way:

For any parabola in the form

y + Ax^2 + Bx + C

the x of the vertex is -B/(2A)

so in our case -1/3

You then sub that back into your equation to find the y of the vertex,

for ours ...

y = 3(1/9) + 1/3 - 2 = 2/3 - 2

= -4/3

Let me know if this answers is sufficient.

- Math -
**Clair**, Tuesday, December 8, 2009 at 11:53pmThanks!

**Related Questions**

Math (Help This Will Be on My Test Tomorrow!) - y= ax^2+bx-4. How would i find ...

Algebra 1 parabola's - I have a graph with a parabola on it and asked to write ...

Math - a parabola has vertex (-6,-12) AND PASSES THROUGH (6,24) find its ...

maths - how do i find out the the equation of the line of symmetry for f(x)=ax^2...

math - Hello. Please, help me solve this: Parabola y = ax^2 + bx + c passes ...

Math - How do i find the equation of a parabola in the form ax^2+bx+c?

Algebra - Consider the graph of the equation y=ax^2+bx+c, when a does not equal ...

alebra - write the vertex form of a parabola that satisfies the conditions given...

Math - 2x(x+3) = 0 Is there a way to solve that using the below methods? ...

Algebra - The formula is y=ax^2+bx+c I also gave the wrong problems, they are...