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I need help in finding the vertex of a parabola using an equation in this form: Ax^2 + Bx+C
I have a test on this tomorrow.
For example: 3x^2 +1x - 2
How would I find the vertex in this?

  • Math - ,

    Unless you are instructed to do it in a certain way, here is the simplest and quickest way:
    For any parabola in the form
    y + Ax^2 + Bx + C
    the x of the vertex is -B/(2A)
    so in our case -1/3
    You then sub that back into your equation to find the y of the vertex,
    for ours ...
    y = 3(1/9) + 1/3 - 2 = 2/3 - 2
    = -4/3

    Let me know if this answers is sufficient.

  • Math - ,


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